What is the output of the following snippet? def fun(x): if x % 2 == 0: return 1 else: return 2 print(fun(fun(2)))

def fun(x):
    if x % 2 == 0:
        return 1
    else:
        return 2
 
 
print(fun(fun(2)))

• 2
• the code will cause a runtime error
• 1
• 2None

Explanation: The print() function in line 8 takes the fun() function as its argument, which takes another fun() function as its argument, which in turn takes the value 2 as its argument.

Let’s analyze the function calls, starting with the right-most ones:

• the fun(2) call – x is assigned the value of 2, so x % 2 = 0, so the comparison 0 == 0 evaluates to True, and the function returns 1, which is passed to the “left” fun() function as its argument,
• the fun(1) call – x is assigned the value of 1, so x % 2 = 1, so the comparison 1 == 0 evaluates to False, which means the function returns 2, which is passed to the print() function as its argument. Therefore, 2 is printed to the screen.

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