What is the expected behavior of the following program? try: print(5/0) break except: print(“Sorry, something went wrong…”) except (ValueError, ZeroDivisionError): print(“Too bad…”)

try:
    print(5/0)
    break
except:
    print("Sorry, something went wrong...")
except (ValueError, ZeroDivisionError):
    print("Too bad...")

• The program will cause a ValueError exception and output a default error message.
• The program will raise an exception handled by the first except block.
• The program will cause a SyntaxError exception.
• The program will cause a ValueError exception and output the following message: Too bad…
• The program will cause a ZeroDivisionError exception and output the following message: Too bad…
• The program will cause a ZeroDivisionError exception and output a default error message.

Explanation: The program will raise a SyntaxError exception, because the break statement used in the try block violates Python’s grammar rules (the break instruction must be used in a loop). When the code is run, before it is executed, the Python interpreter first parses it and converts it to Python byte code. If the parser encounters a syntax error which has a fatal effect on the program, it won’t be able to parse the code successfully, and will raise a SyntaxError.

Remember that the parser analyzes the program before its execution, so if it encounters a syntax error, the program will not be executed. If your code has no syntax errors, the program is executed and may raise other types of exceptions.

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