What is the expected output of the following code? try: print(“5″/0) except ArithmeticError: print(“arith”) except ZeroDivisionError: print(“zero”) except: print(“some”)

try:
    print("5"/0)
except ArithmeticError:
    print("arith")
except ZeroDivisionError:
    print("zero")
except:
    print("some")

• zero
• arith
• 0
• some

Explanation: Let’s analyze this code snippet:

• The print function inside the try block is executed.
• If you look closely, “5” is a string, and it is divided by an integer zero.
• No ArithmeticError nor ZeroDivisionError is raised.
• Instead, a TypeError exception is raised, which will fall under the nameless except.
• The word some is printed in the console.

More Questions: Python Essentials 2 – Module 2 Test