What is the expected result of executing the following code? def I(): s = ‘abcdef’ for c in s[::2]: yield c for x in I(): print(x, end=”)

def I():
    s = 'abcdef'
    for c in s[::2]:
        yield c
 
 
for x in I():
    print(x, end='')

• It will print ace
• It will print bdf
• It will print an empty line
• It will print abcdef

Explanation: Let’s analyze this code snippet:

• The code begins by executing the for x in I(): loop.
• It uses the x variable to iterate through what I(): yields, and outputs it on the same line due to the end=” argument in the print function.
• Once the I(): iterator is invoked, it initializes a string that contains the characters s = ‘abcdef’.
• A for loop iterates though the characters within the s string using the c variable.
• Due to the [::2] notation, the loop will only iterate through every two characters, yielding one on each iteration. In other words, it begins on the first character, skips to the third, and finally to the fifth.
• Since there is no seventh character, the execution comes to an end.
• The characters ace are printed in the console.

More Questions: Python Essentials 2 – Module 4 Test