What is the expected result of executing the following code? def fun(n): s = ‘+’ for i in range(n): s += s yield s for x in fun(2): print(x, end=”);

def fun(n):
    s = '+'
    for i in range(n):
        s += s
        yield s
 
 
for x in fun(2):
    print(x, end='');

• It will print ++
• It will print ++++++
• It will print +
• It will print +++

Explanation: Let’s analyze this code snippet:

• The code begins by executing the for x in fun(2): loop.
• It uses the x variable to iterate through what fun(2): yields, and outputs it on the same line due to the end=” argument in the print function.
• Once the fun(2): iterator is invoked, it initializes a string that contains the character s = ‘+’.
• A for loop uses the range function with 2 as its argument, which was sent to the iterator when it was invoked. The for loop will iterate twice (the values for the i variable are 0 and 1).
• In the first iteration, the s += s operation is applied to the string, and the new string s = ‘++’ is yielded and outputted in the console.
• In the second iteration, the s += s operation is again applied to the last produced string, and the new string s = ‘++++’ is yielded and outputted in the console.
• The final result shown in the console is ++++++ .

More Questions: Python Essentials 2 – Module 4 Test