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What is the expected result of the following code? from datetime import datetime datetime = datetime(2019, 11, 27, 11, 27, 22) print(datetime.strftime(‘%y/%B/%d %H:%M:%S’))

Questions BankCategory: Python Essentials 2What is the expected result of the following code? from datetime import datetime datetime = datetime(2019, 11, 27, 11, 27, 22) print(datetime.strftime(‘%y/%B/%d %H:%M:%S’))
What is the expected result of the following code?

from datetime import datetime
 
datetime = datetime(2019, 11, 27, 11, 27, 22)
print(datetime.strftime('%y/%B/%d %H:%M:%S'))
  • 19/November/27 11:27:22
  • 19/11/27 11:27:22
  • 2019/Nov/27 11:27:22
  • 2019/11/27 11:27:22

Explanation: Let’s analyze this code snippet:

  • The first line imports the datetime function from the datetime module.
  • The second line creates a datetime object named datetime. The arguments represent the year, month, day, hours, minutes, and seconds.
  • The third line formats the date using the strftime method.
  • The %y argument formats the year without the century digits, and the result is 19.
  • The %B argument formats the month to its full name, and the result is November.
  • The %d argument formats the day to two digits. In this case, the result stays the same, which is 27.
  • The %H argument formats the hours to a 24 hour format. In this case, the result stays the same, which is 11.
  • The %M argument formats the minutes to two digits. In this case, the result stays the same, which is 27.
  • The %S argument formats the seconds to two digits. In this case, the result stays the same, which is 22.
  • The arguments are separated by slashes and colons. The output printed in the console is 19/November/27 11:27:22.

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