Placing a debugger; statement in the program code will:

• cause the console to display the completion status of the statement preceding the debugger.
• put the interpreter into report mode, which will cause the console to print out all sequentially executed commands.
• pause the program with the ability to continue, as long as the execution environment supports “debugging functionality”.
• stop the program without the ability to continue, as long as the execution environment supports “debugging functionality”.

More Questions: JavaScript Essentials 1 – JSE1: Final Test