What is the expected result of executing the following code?
class I: def __init__(self): self.s = 'abc' self.i = 0 def __iter__(self): return self def __next__(self): if self.i == len(self.s): raise StopIteration v = self.s[self.i] self.i += 1 return v for x in I(): print(x, end='')
- The code will print 210
- The code will print cba
- The code will print abc
- The code will print 012
Explanation: Let’s analyze this code snippet:
- First, a for loop using the x variable iterates through the already defined I() generator.
- The generator class initializes the self.s = ‘abc’ and self.i = 0 variables within the constructor.
- The __next__ method checks if the value in i is equal to the length of s.
- Since it is not, v is assigned the first character of s, which is a, i is incremented by one, v is returned and printed in the console.
- The end=” argument in the print function will prevent new lines, so all the outputs will be shown on the same line.
- The iteration continues for the remaining characters in s. The b and c characters are also printed in the console.
- When the condition self.i == len(self.s) becomes true, a StopIteration is raised. This terminates the execution.
More Questions: Python Essentials 2 (PE2) Course Final Test
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