What is the output of the following snippet? def fun(x, y): if x == y: return x else: return fun(x, y-1) print(fun(0, 3))

def fun(x, y):
    if x == y:
        return x
    else:
        return fun(x, y-1)
 
 
print(fun(0, 3))

• the snippet will cause a runtime error
• 0
• 1
• 2

Explanation: The following snippet is an example of a recursive function.

The following two arguments are sent to the fun(x, y) function: 0 and 3. The result of the comparison x == y is False, so the else: block is triggered.

In the else: block, the fun(x, y-1) function call is returned, and this time the following two arguments are sent: x = 0, and y = 3 – 1 = 2. The process is repeated (x = 0, y = 2 – 1 = 1, and x = 0, y = 1 – 1 = 0) until the value assigned to the y variable is equal to 0, in which case the result of the x == ycomparison is True, and the function returns the x value of 0.

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