What code would you insert instead of the comment to obtain the expected output? Expected output: [box type="shadow" align="" class="" width=""]a b c[/box] Code: dictionary = {} my_list = [‘a’, ‘b’, ‘c’, ‘d’] for i in range(len(my_list) – 1): dictionary[my_list[i]] = (my_list[i], ) for i in sorted(dictionary.keys()): k = dictionary[i] # Insert your code here.

What code would you insert instead of the comment to obtain the expected output?
Expected output:
[box type="shadow" align="" class="" width=""]a
b
c[/box] Code:

dictionary = {}
my_list = ['a', 'b', 'c', 'd']
 
for i in range(len(my_list) - 1):
    dictionary[my_list[i]] = (my_list[i], )
 
for i in sorted(dictionary.keys()):
    k = dictionary[i]
    # Insert your code here.

• print(k[‘0’])
• print(k[0])
• print(k[“0”])
• print(k)

Explanation: Let’s analyze the code:

• an empty dictionary is created,
• a list named my_list with the elements [‘a’, ‘b’, ‘c’, ‘d’] is created,
• a for loop in the range of the list length minus one (0 to 3) is initialized, and the values that the i variable iterates are a,b,c,d,
• for each iteration, a key-pair value will be inserted in the dictionary. The key is a String, and the value is a tuple with one element,
• the resulting dictionary is: {‘a’: (‘a’,), ‘b’: (‘b’,), ‘c’: (‘c’,)}
• another for loop is initialized, and the i variable iterates the sorted dictionary keys,
• the k variable stores the value for each key,
• since it is a tuple, it is necessary to select the print(k[0]) option in order to print the first and only element.

More Questions: Python Essentials 1 – Module 4 Test