What is the output of the following snippet? def fun(x): if x % 2 == 0: return 1 else: return print(fun(fun(2)) + 1)

def fun(x):
    if x % 2 == 0:
        return 1
    else:
        return
 
 
print(fun(fun(2)) + 1)

• 2
• the code will cause a runtime error
• None
• 1

Explanation: Let’s analyze the code:

• the inner parentheses in the print function are executed first,
• the fun function is invoked with the integer 2 as an argument,
• the if conditional 2 % 2 == 0 returns True, so the fun function returns 1,
• the fun function is invoked with the integer 1 as its argument,
• the if conditional 1 % 2 == 0 returns False, so the fun function returns None,
• The arithmetic operation None + 1 is attempted,
• A runtime error is generated: TypeError: unsupported operand type(s) for +: ‘NoneType’ and ‘int’.

More Questions: Python Essentials 1 – Module 4 Test